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📰 Now, since $ d(x) $ is linear, we need another condition. But we only have two point evaluations and the form. However, we can express $ h(x) $ in terms of finite differences. For a quadratic polynomial, the second difference is constant: 📰 But we only have $ h(2024) = 2024 $, $ h(2025) = 2025 $. Compute $ h(2026) = h(2025) + d(2025) = 2025 + (2a(2025) + a + b) $ 📰 But from $ d(x) = 2a x + (a + b) $, and $ d(2024) = 1 $. We need $ d(2025) = 2a(2025) + a + b $. Express in terms of knowns. 📰 This Board And Batten Wall Transforms Homes You Never Expected 6250779 📰 Charlie Kirk Exposes The Currency That Will Shatter Your Savings Forever 2243249 📰 Florida Lottery Winning Numbers Last Night 9183895 📰 Delta Pilots Face Nightmare Dl153 Shot Down By Stormpassengers Left In Shock As Emergency Landing Unfolds Live 8740033 📰 She Wore Black In Blue Dress Youll Never Guess Her Hidden Secret 6054069 📰 Phet Simulations 247368 📰 Secrets Beneath The Surface Of This Place That Threatens Your Soul 8684569 📰 Freeform Shows 6800815 📰 The Mega Surge Market Cap In Stock Surges Today Are You Ready For The Movement 5797573 📰 The Lifesaving Secret To Choosing Between 401K And Ira Youve Never Heard 3527879 📰 Popular This Surprising Reason Will Change How You See The Trend 7644886 📰 Send Money To Another Bank Wells Fargo 8356535 📰 64 Oz To Gallon 4977883 📰 This Hidden Truth About Nassau Boces Will Blow Your Mindinside The Untold Story 8945561 📰 What Is Hydroxyapatite 3091962