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we're all trying to find the guy who did this - Malaeb

📅 May 5, 2026 👤 scraface

May 05, 2026

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Alternatively, divide: $3025 \div 9 = 336 imes 9 = 3024$, remainder $...
Thus, the remainder is $1$.
Therefore, the answer is $oxed{1}$.
Question: What is the greatest common divisor of $3^{15} - 1$ and $3^9...
Solution: Use the property:
\gcd(a^m - 1, a^n - 1) = a^{\gcd(m,n)} - 1, \quad ext{for } a > 1.
\gcd(3^{15} - 1, 3^9 - 1) = 3^{\gcd(15,9)} - 1.
Now compute $\gcd(15,9) = 3$.
\gcd(3^{15} - 1, 3^9 - 1) = 3^3 - 1 = 27 - 1 = 26.
Therefore, the greatest common divisor is $oxed{26}$.**Question:** An...

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