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A circle is inscribed in an equilateral triangle with side length 12 cm. What is the area of the circle?
In an equilateral triangle, the inradius \( r = \frac{s\sqrt{3}}{6} \), where \( s = 12 \).
So, \( r = \frac{12\sqrt{3}}{6} = 2\sqrt{3} \).

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