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nvidia geforce rtx 5090 founders edition - Malaeb

📅 May 4, 2026 👤 scraface

May 04, 2026

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Conclusion: the remainder is constant \( -1 \)
Alternatively, polynomial division confirms:
Divide \( u^4 + 0u^3 + 0u^2 + 0u + 3 \) by \( u^2 - 2u + 2 \)
First: \( u^4 \div u^2 = u^2 \), multiply: \( u^2(u^2 - 2u + 2) = u^4...
Subtract: \( (u^4 + 0u^3 + 0u^2) - (u^4 - 2u^3 + 2u^2) = 2u^3 - 2u^2 \...
Bring down: \( +0u + 3 \), now divide \( 2u^3 \div u^2 = 2u \)
Multiply: \( 2u(u^2 - 2u + 2) = 2u^3 - 4u^2 + 4u \)
Subtract: \( (2u^3 - 2u^2 + 0u) - (2u^3 - 4u^2 + 4u) = 2u^2 - 4u \)
Now: \( 2u^2 \div u^2 = 2 \), multiply: \( 2(u^2 - 2u + 2) = 2u^2 - 4u...
Subtract: \( (2u^2 - 4u + 3) - (2u^2 - 4u + 4) = -1 \)

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