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League of Legend Download Mac - Malaeb

📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 - 2\sqrt{30} \approx 12 - 10.95 = 1.05

📌 \Delta h = 12 - \sqrt{120} = 12 - 2\sqrt{30}

📌 But compute exactly:

📌 \sqrt{120} = \sqrt{4 \cdot 30} = 2\sqrt{30}

📌 So decrease in height is \( 12 - 2\sqrt{30} \) meters.

📌 However, the problem asks for how far the top slides down — which is the difference:

📌 - 2\sqrt{30}

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Initial area:
A_1 = \frac{\sqrt{3}}{4} \cdot 12^2 = \frac{\sqrt{3}}{4} \cdot 144 = 3...
New side length is \(12 + 2 = 14\) cm, so the new area \(A_2\) is:
A_2 = \frac{\sqrt{3}}{4} \cdot 14^2 = \frac{\sqrt{3}}{4} \cdot 196 = 4...
Increase in area:
\Delta A = A_2 - A_1 = 49\sqrt{3} - 36\sqrt{3} = 13\sqrt{3} \text{ cm}...
Thus, the area increases by \(\boxed{13\sqrt{3}}\) square centimeters.
Question:** The radius of a sphere is tripled. By what factor does the...
The volume \(V\) of a sphere with radius \(r\) is:
Let the original radius be \(r\), so original volume is:

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