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📅 May 4, 2026 👤 scraface

May 04, 2026

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📝 Recent Posts

We want \( 80k + 16 \equiv 76 \pmod{100} \), so:
80k \equiv 60 \pmod{100}
Divide by 20:
4k \equiv 3 \pmod{5} \implies k \equiv 2 \pmod{5} \quad \text{(since }...
Thus, \( k = 5m + 2 \), so \( n = 10(5m + 2) + 4 = 50m + 24 \). The sm...
Now consider \( n \equiv 6 \pmod{10} \): \( n = 10k + 6 \).
n^2 = 100k^2 + 120k + 36 \equiv 20k + 36 \pmod{100}
Set \( 20k + 36 \equiv 76 \pmod{100} \):
20k \equiv 40 \pmod{100} \implies k \equiv 2 \pmod{5}
So \( k = 5m + 2 \), \( n = 10(5m + 2) + 6 = 50m + 26 \). Smallest \(...

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