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📅 May 4, 2026 👤 scraface

May 04, 2026

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📝 Recent Posts

Solución: Este es un problema de distribución hipergeométrica. Tenemos...
Queremos la probabilidad de que exactamente 2 sean rojas. La fórmula p...
P(X = k) = \frac{\binom{K}{k} \binom{N-K}{n-k}}{\binom{N}{n}}
Donde:
$ N = 12 $ (total de bolas),
$ K = 5 $ (bolas rojas),
$ n = 4 $ (seleccionadas),
$ k = 2 $ (bolas rojas seleccionadas).
Sustituyendo:
P(X = 2) = \frac{\binom{5}{2} \binom{7}{2}}{\binom{12}{4}}

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